What is the answer to solvefor y,y(1+p^2)=a ?

The answer to solvefor y,y(1+p^2)=a is y= a/(1+p^2);\quad p\ne i,p\ne-i

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solvefor y,y(1+p^2)=a

solve for

y, y (1 + p^{2}) = a

y = \frac{a}{1 + p ^{2}}; p \neq = i, p \neq = - i

Solution steps

y (1 + p^{2}) = a

Divide both sides by

1 + p^{2}; p \neq = i, p \neq = - i

y = \frac{a}{1 + p ^{2}}; p \neq = i, p \neq = - i

a, a + b = 0 a^{2021} + b^{2021}

- 3 x - 2 = 6 x

x, 6 x + 9 - 4 y + 4 = - 8 x + 16 + 10 y + 25

a = 2 x - 9

x + 3 (5 x - 1) = 1

What is the answer to solvefor y,y(1+p^2)=a ?
The answer to solvefor y,y(1+p^2)=a is y= a/(1+p^2);\quad p\ne i,p\ne-i