What is the answer to solvefor f,f=(((i)^{1/2})^i)^{1/2} ?

The answer to solvefor f,f=(((i)^{1/2})^i)^{1/2} is f=(i^{1/2})^{i/2}

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solvefor f,f=(((i)^{1/2})^i)^{1/2}

solve for

f, f = (((i)^{\frac{1}{2}})^{i})^{\frac{1}{2}}

f = (i^{\frac{1}{2}})^{\frac{i}{2}}

Solution steps

f = (((i)^{\frac{1}{2}})^{i})^{\frac{1}{2}}

Simplify

((i^{\frac{1}{2}})^{i})^{\frac{1}{2}} : (i^{\frac{1}{2}})^{\frac{i}{2}}

f = (i^{\frac{1}{2}})^{\frac{i}{2}}

t, b = b^{0} e - m \cdot g \frac{h}{r} \cdot t

x = \frac{( 7 + 4 3 )}{( 7 - 4 3 )}

x, 2 x - 9 y = 9

5 - x = x - 1

x, 3010 = 25 x + 45 y

What is the answer to solvefor f,f=(((i)^{1/2})^i)^{1/2} ?
The answer to solvefor f,f=(((i)^{1/2})^i)^{1/2} is f=(i^{1/2})^{i/2}