What is the answer to solvefor f,f(x-1)=f-3x^3+6x^2+1 ?

The answer to solvefor f,f(x-1)=f-3x^3+6x^2+1 is f=(-3x^3+6x^2+1)/(x-2);\quad x\ne 2

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solvefor f,f(x-1)=f-3x^3+6x^2+1

solve for

f, f (x - 1) = f - 3 x^{3} + 6 x^{2} + 1

f = \frac{- 3 x ^{3} + 6 x ^{2} + 1}{x - 2}; x \neq = 2

Solution steps

f (x - 1) = f - 3 x^{3} + 6 x^{2} + 1

Expand

f (x - 1) : x f - f

x f - f = f - 3 x^{3} + 6 x^{2} + 1

Move

f

to the left side

x f - 2 f = - 3 x^{3} + 6 x^{2} + 1

Factor

x f - 2 f : f (x - 2)

f (x - 2) = - 3 x^{3} + 6 x^{2} + 1

Divide both sides by

x - 2; x \neq = 2

f = \frac{- 3 x ^{3} + 6 x ^{2} + 1}{x - 2}; x \neq = 2

c, a^{x} - b^{x} - c = 0

z = 5 + 10 i - 2 i

x, 2 (3 x + 4 y) = 4 x + 12 y

\frac{( 3 x - 6 )}{4} - \frac{( x - 1 )}{2} = x

g, g (s) = k \frac{( s ^{2} + 4 )}{( s ^{2} + 2 )}

What is the answer to solvefor f,f(x-1)=f-3x^3+6x^2+1 ?
The answer to solvefor f,f(x-1)=f-3x^3+6x^2+1 is f=(-3x^3+6x^2+1)/(x-2);\quad x\ne 2