What are the solutions to the equation x^2+24^2=25^2 ?

The solutions to the equation x^2+24^2=25^2 are x=7,x=-7

Find the zeros of x^2+24^2=25^2

The zeros of x^2+24^2=25^2 are x=7,x=-7

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x^{2} + 2 4^{2} = 2 5^{2}

x = 7, x = - 7

Solution steps

x^{2} + 2 4^{2} = 2 5^{2}

Move

2 4^{2}

to the right side

x^{2} = 49

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 49, x = - 49

49 = 7

- 49 = - 7

x = 7, x = - 7

16 (n + 6) = 4 (24 + 4 n)

2 x^{2} - 14 x + 20

lo g_{7} (\frac{1}{49}) = x

225 \cdot \frac{π}{180}

x + 10 \leq 4

What are the solutions to the equation x^2+24^2=25^2 ?
The solutions to the equation x^2+24^2=25^2 are x=7,x=-7
Find the zeros of x^2+24^2=25^2
The zeros of x^2+24^2=25^2 are x=7,x=-7