What are the solutions to the equation -4x^2+27x+2=0 ?

The solutions to the equation -4x^2+27x+2=0 are x=-(-27+sqrt(761))/8 ,x=(27+sqrt(761))/8

Find the zeros of -4x^2+27x+2=0

The zeros of -4x^2+27x+2=0 are x=-(-27+sqrt(761))/8 ,x=(27+sqrt(761))/8

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- 4 x^{2} + 27 x + 2 = 0

x = - \frac{- 27 + 761}{8}, x = \frac{27 + 761}{8}

Decimal Notation

x = - 0.07327 \dots, x = 6.82327 \dots

Solution steps

- 4 x^{2} + 27 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 27 \pm 2 7 ^{2} - 4 ( - 4 ) \cdot 2}{2 ( - 4 )}

2 7^{2} - 4 (- 4) \cdot 2 = 761

x_{1, 2} = \frac{- 27 \pm 761}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 27 + 761}{2 ( - 4 )}, x_{2} = \frac{- 27 - 761}{2 ( - 4 )}

x = \frac{- 27 + 761}{2 ( - 4 )} : - \frac{- 27 + 761}{8}

x = \frac{- 27 - 761}{2 ( - 4 )} : \frac{27 + 761}{8}

The solutions to the quadratic equation are:

x = - \frac{- 27 + 761}{8}, x = \frac{27 + 761}{8}

\frac{x ^{2} - 9}{5} - \frac{x ^{2} - 4}{15} \leq \frac{1 - 2 x}{3}

5 x + 4 (3 x - 5) = x - 4

\frac{( 3 - ( ( 2.001 ) ^{2} - 1 ) )}{2 - 2.001}

1 < y \leq 3

\frac{4}{5} - 1

What are the solutions to the equation -4x^2+27x+2=0 ?
The solutions to the equation -4x^2+27x+2=0 are x=-(-27+sqrt(761))/8 ,x=(27+sqrt(761))/8
Find the zeros of -4x^2+27x+2=0
The zeros of -4x^2+27x+2=0 are x=-(-27+sqrt(761))/8 ,x=(27+sqrt(761))/8