What is the answer to (3x+2)(3x-2)-(3x-1)^2=5 ?

The answer to (3x+2)(3x-2)-(3x-1)^2=5 is x= 5/3

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(3x+2)(3x-2)-(3x-1)^2=5

(3 x + 2) (3 x - 2) - (3 x - 1)^{2} = 5

x = \frac{5}{3}

Decimal

x = 1.66666 \dots

Solution steps

(3 x + 2) (3 x - 2) - (3 x - 1)^{2} = 5

Expand

(3 x + 2) (3 x - 2) - (3 x - 1)^{2} : 6 x - 5

6 x - 5 = 5

Move

5

to the right side

6 x = 10

Divide both sides by

6

x = \frac{5}{3}

p = 2 \cdot 1 0^{5} \cdot n \cdot m^{- 2}

x + 1.05 x + 1.1 x + 1.15 x = 10400

x, \frac{x}{2} + \frac{y}{4} = - 1

7 x + \frac{14}{3} - 17 - 3 \frac{x}{5} = 6 x - 4 x + \frac{2}{3} - 5

\frac{5 x - 7}{2} = \frac{( 5 x )}{2 + 15}

What is the answer to (3x+2)(3x-2)-(3x-1)^2=5 ?
The answer to (3x+2)(3x-2)-(3x-1)^2=5 is x= 5/3
Solve for x: (3x+2)(3x-2)-(3x-1)^2=5
The solution is x= 5/3