What is the answer to solvefor a, a/b-5/12 b= 1/12 b(12a-5) ?

The answer to solvefor a, a/b-5/12 b= 1/12 b(12a-5) is a=0;\quad b\ne 0

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solvefor a, a/b-5/12 b= 1/12 b(12a-5)

solve for

a, \frac{a}{b} - \frac{5}{12} b = \frac{1}{12} b (12 a - 5)

a = 0; b \neq = 0

Solution steps

\frac{a}{b} - \frac{5}{12} b = \frac{1}{12} b (12 a - 5)

Move

\frac{5}{12} b

to the right side

\frac{a}{b} = ab

Multiply both sides by

b

a = a b^{2}; b \neq = 0

Move

a b^{2}

to the left side

a - a b^{2} = 0; b \neq = 0

Factor

a - a b^{2} : a (1 - b^{2})

a (1 - b^{2}) = 0; b \neq = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a = 0; b \neq = 0

\frac{x}{3} + \frac{1}{2} = \frac{x}{6} + \frac{( - 5 )}{12}

\frac{( 3 x + 8 )}{16} - (\frac{( 12 x - 6 )}{( 15 - 30 )}) + \frac{x}{3} = \frac{( 7 x )}{12} - (\frac{( 2 x + 16 )}{32})

(\frac{31}{7} - \frac{13}{14}) \cdot x = \frac{12}{7}

x, p = 3 x + 3 x + 5 gx + 2

x, 9 y - 9 x = 27

What is the answer to solvefor a, a/b-5/12 b= 1/12 b(12a-5) ?
The answer to solvefor a, a/b-5/12 b= 1/12 b(12a-5) is a=0;\quad b\ne 0