What is the answer to solvefor f,z=(x+y)f(x^2y^2) ?

The answer to solvefor f,z=(x+y)f(x^2y^2) is f= z/((x+y)x^2y^2);\quad (x+y)x^2y^2\ne 0

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solvefor f,z=(x+y)f(x^2y^2)

solve for

f, z = (x + y) f (x^{2} y^{2})

f = \frac{z}{( x + y ) x ^{2} y ^{2}}; (x + y) x^{2} y^{2} \neq = 0

Solution steps

z = (x + y) f (x^{2} y^{2})

Switch sides

(x + y) f x^{2} y^{2} = z

Divide both sides by

(x + y) x^{2} y^{2}; (x + y) x^{2} y^{2} \neq = 0

f = \frac{z}{( x + y ) x ^{2} y ^{2}}; (x + y) x^{2} y^{2} \neq = 0

x, 3 z - 2 x + 6 = 0

y, 2 y + 1 = x

x = \frac{( 4 + 5 )}{( 4 - 5 )}

x, 4 x = 17 - \frac{( x - y )}{8}

f = 5 (\frac{1}{1 0 ^{2}}) + 2 (\frac{1}{10}) - 1

What is the answer to solvefor f,z=(x+y)f(x^2y^2) ?
The answer to solvefor f,z=(x+y)f(x^2y^2) is f= z/((x+y)x^2y^2);\quad (x+y)x^2y^2\ne 0