What is the answer to solvefor a,c-a+a+a+a=90-10 ?

The answer to solvefor a,c-a+a+a+a=90-10 is a=(80-c)/2

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solvefor a,c-a+a+a+a=90-10

solve for

a, c - a + a + a + a = 90 - 10

a = \frac{80 - c}{2}

Solution steps

c - a + a + a + a = 90 - 10

Add similar elements:

- a + a + a + a = 2 a

c + 2 a = 90 - 10

Subtract the numbers:

90 - 10 = 80

c + 2 a = 80

Move

c

to the right side

2 a = 80 - c

Divide both sides by

2

a = \frac{80 - c}{2}

z, r = (x - t) (x^{2} - y) (y^{2} - z)

\frac{1}{3} \cdot x + \frac{2}{5} \cdot x + 12 = x

3 x + 35 x + 2 = 45

a, 900 a + 6 b = 7.9

x, 4 x + y - 2 z = - 3

What is the answer to solvefor a,c-a+a+a+a=90-10 ?
The answer to solvefor a,c-a+a+a+a=90-10 is a=(80-c)/2