What are the solutions to the equation (5x-2)(-x+3)=0 ?

The solutions to the equation (5x-2)(-x+3)=0 are x= 2/5 ,x=3

Find the zeros of (5x-2)(-x+3)=0

The zeros of (5x-2)(-x+3)=0 are x= 2/5 ,x=3

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(5 x - 2) (- x + 3) = 0

x = \frac{2}{5}, x = 3

Decimal Notation

x = 0.4, x = 3

Solution steps

(5 x - 2) (- x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x - 2 = 0 or - x + 3 = 0

Solve

5 x - 2 = 0 : x = \frac{2}{5}

Solve

- x + 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = 3

2 x - 1 \leq x

∣ 3 x + 1 ∣ + 10 = 4

1.8 (\frac{3}{2}) 0.08341 (x - 700) = - 2 (15 - 7.5)

2 k^{4} + 4 k^{3} - 70 k^{2}

5 x - 19 \leq 1 or - 4 x + 3 < - 6

What are the solutions to the equation (5x-2)(-x+3)=0 ?
The solutions to the equation (5x-2)(-x+3)=0 are x= 2/5 ,x=3
Find the zeros of (5x-2)(-x+3)=0
The zeros of (5x-2)(-x+3)=0 are x= 2/5 ,x=3