What is the answer to solvefor x,-3xy+3x+y=0 ?

The answer to solvefor x,-3xy+3x+y=0 is x=-y/(3(-y+1));\quad y\ne 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,-3xy+3x+y=0

solve for

x, - 3 x y + 3 x + y = 0

x = - \frac{y}{3 ( - y + 1 )}; y \neq = 1

Solution steps

- 3 x y + 3 x + y = 0

Move

y

to the right side

- 3 x y + 3 x = - y

Factor

- 3 x y + 3 x : 3 x (- y + 1)

3 x (- y + 1) = - y

Divide both sides by

3 (- y + 1); y \neq = 1

x = - \frac{y}{3 ( - y + 1 )}; y \neq = 1

x, y^{1} + x y + x \cdot y^{3} = 0

\frac{4 x}{3 - 2} = \frac{2 x + 3}{3 - 1}

\frac{x}{2} - 1 = 4

3 = 0.8 q + 2

7 t + 3 = 8 + 7 t

What is the answer to solvefor x,-3xy+3x+y=0 ?
The answer to solvefor x,-3xy+3x+y=0 is x=-y/(3(-y+1));\quad y\ne 1