What is the answer to solvefor x,y(n)=x(n)+x(n-1) ?

The answer to solvefor x,y(n)=x(n)+x(n-1) is x=(ny)/(2n-1);\quad n\ne 1/2

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solvefor x,y(n)=x(n)+x(n-1)

solve for

x, y (n) = x (n) + x (n - 1)

x = \frac{n y}{2 n - 1}; n \neq = \frac{1}{2}

Solution steps

y (n) = x (n) + x (n - 1)

Switch sides

x n + x (n - 1) = y n

n x + x (n - 1) = n y

Expand

x (n - 1) : n x - x

n x + n x - x = n y

Add similar elements:

n x + n x = 2 n x

2 n x - x = n y

Factor

2 n x - x : x (2 n - 1)

x (2 n - 1) = n y

Divide both sides by

2 n - 1; n \neq = \frac{1}{2}

x = \frac{n y}{2 n - 1}; n \neq = \frac{1}{2}

x, x m o d = 5

\frac{( 4 + x )}{7} - \frac{( x + 6 )}{3} = - 1

3 x + 2 = 27

\frac{( 3 x - 1 )}{5} = 4

y, 8 y = 6 x^{2} - 10 x - 5 x^{- 2}

What is the answer to solvefor x,y(n)=x(n)+x(n-1) ?
The answer to solvefor x,y(n)=x(n)+x(n-1) is x=(ny)/(2n-1);\quad n\ne 1/2