What is the answer to solvefor x,[f]^2-[f]^2=f ?

The answer to solvefor x,[f]^2-[f]^2=f is True for all x;\quad 0=f

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solvefor x,[f]^2-[f]^2=f

solve for

x, [f]^{2} - [f]^{2} = f

True for all x; 0 = f

Solution steps

[f]^{2} - [f]^{2} = f

Simplify

f^{2} - f^{2} : 0

0 = f

Both sides are equal

True for all x; 0 = f

\frac{( \frac{( 2 x )}{5} - 1 )}{( - 5 )} = \frac{1}{7}

a, 5 a = \frac{( ( b + 2 ) ^{\frac{1}{2}} )}{3}

(x - 1) = 2 5^{2}

lo g_{10} (5) x = 4

a, 1 a + 2 b + 5 c + 10 d = 0

What is the answer to solvefor x,[f]^2-[f]^2=f ?
The answer to solvefor x,[f]^2-[f]^2=f is True for all x;\quad 0=f