What are the solutions to the equation x^2=9-8x ?

The solutions to the equation x^2=9-8x are x=1,x=-9

Find the zeros of x^2=9-8x

The zeros of x^2=9-8x are x=1,x=-9

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x^{2} = 9 - 8 x

x = 1, x = - 9

Solution steps

x^{2} = 9 - 8 x

Move

8 x

to the left side

x^{2} + 8 x = 9

Move

9

to the left side

x^{2} + 8 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 9) = 10

x_{1, 2} = \frac{- 8 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 10}{2 \cdot 1}, x_{2} = \frac{- 8 - 10}{2 \cdot 1}

x = \frac{- 8 + 10}{2 \cdot 1} : 1

x = \frac{- 8 - 10}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 1, x = - 9

(x - 2) (x + 2) - 7 (x - 1) = 21

5 - 3 \cdot \frac{z - z ^{- 1}}{2 \cdot i}

\frac{2}{1 + 2}

11 x + 11 = - 2 x - 8

b^{2} + 1 1^{2} = 2 1^{2}

What are the solutions to the equation x^2=9-8x ?
The solutions to the equation x^2=9-8x are x=1,x=-9
Find the zeros of x^2=9-8x
The zeros of x^2=9-8x are x=1,x=-9