What is the answer to solvefor y, 1/3*x^2-sqrt(11x)+y=0 ?

The answer to solvefor y, 1/3*x^2-sqrt(11x)+y=0 is y=-1/3 x^2+sqrt(11)sqrt(x)

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solvefor y, 1/3*x^2-sqrt(11x)+y=0

solve for

y, \frac{1}{3} \cdot x^{2} - 11 x + y = 0

y = - \frac{1}{3} x^{2} + 11 x

Solution steps

\frac{1}{3} x^{2} - 11 x + y = 0

Apply radical rule:

assuming

a \geq 0, b \geq 0

\frac{1}{3} x^{2} - 11 x + y = 0

Move

\frac{1}{3} x^{2}

to the right side

- 11 x + y = - \frac{1}{3} x^{2}

Move

11 x

to the right side

y = - \frac{1}{3} x^{2} + 11 x

x, f (x - 2) = f \frac{( x )}{4}

0.18 (5 p - 4) = 0.5 p + 0.8

a, m (5 a + b) = q

2 (2) - 3 y = 12

x, y - 3.2 = 1.1 (x - 0.1)

What is the answer to solvefor y, 1/3*x^2-sqrt(11x)+y=0 ?
The answer to solvefor y, 1/3*x^2-sqrt(11x)+y=0 is y=-1/3 x^2+sqrt(11)sqrt(x)