What is the answer to 1/((log_{6)(12))}+1/((log_{2)(12))}=x ?

The answer to 1/((log_{6)(12))}+1/((log_{2)(12))}=x is x= 1/(log_{6)(12)}+1/(log_{2)(12)}

Solve for x: 1/((log_{6)(12))}+1/((log_{2)(12))}=x

The solution is x= 1/(log_{6)(12)}+1/(log_{2)(12)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{1}{( lo g _{6} ( 12 ) )} + \frac{1}{( lo g _{2} ( 12 ) )} = x

x = \frac{1}{lo g _{6} ( 12 )} + \frac{1}{lo g _{2} ( 12 )}

Decimal Notation

x = 1

Solution steps

\frac{1}{( lo g _{6} ( 12 ) )} + \frac{1}{( lo g _{2} ( 12 ) )} = x

Switch sides

x = \frac{1}{( lo g _{6} ( 12 ) )} + \frac{1}{( lo g _{2} ( 12 ) )}

Remove parentheses:

(a) = a

x = \frac{1}{lo g _{6} ( 12 )} + \frac{1}{lo g _{2} ( 12 )}

x, 2 (8 x - 5 y) = 34

x, 141 x + 93 y = 189

\frac{( 4 x )}{2 + 3.6} = 104

a, \frac{a}{b} + \frac{1}{5} = \frac{24}{15}

e (t) = 2 \cdot t + 0.06

What is the answer to 1/((log_{6)(12))}+1/((log_{2)(12))}=x ?
The answer to 1/((log_{6)(12))}+1/((log_{2)(12))}=x is x= 1/(log_{6)(12)}+1/(log_{2)(12)}
Solve for x: 1/((log_{6)(12))}+1/((log_{2)(12))}=x
The solution is x= 1/(log_{6)(12)}+1/(log_{2)(12)}