What is the answer to solvefor k,2^{4n}=15k+1 ?

The answer to solvefor k,2^{4n}=15k+1 is k=(16^n-1)/(15)

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solvefor k,2^{4n}=15k+1

solve for

k, 2^{4 n} = 15 k + 1

k = \frac{1 6 ^{n} - 1}{15}

Solution steps

2^{4 n} = 15 k + 1

Switch sides

15 k + 1 = 2^{4 n}

Simplify

2^{4 n} : 1 6^{n}

15 k + 1 = 1 6^{n}

Move

1

to the right side

15 k = 1 6^{n} - 1

Divide both sides by

15

k = \frac{1 6 ^{n} - 1}{15}

a, - 8 a + 4 b - 8 = 0

x, \frac{1}{2} x = - y + 8

2 x + 5 a = 31

x, g = - 2 f - 3

p, p (t) = 4 t^{3} - s \cdot t^{2} + 7

What is the answer to solvefor k,2^{4n}=15k+1 ?
The answer to solvefor k,2^{4n}=15k+1 is k=(16^n-1)/(15)