What is the answer to x^2+x-6=(x+3)(x+k), k/2 ?

The answer to x^2+x-6=(x+3)(x+k), k/2 is x=-3;\quad k\ne-2

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x^2+x-6=(x+3)(x+k), k/2

x^{2} + x - 6 = (x + 3) (x + k), \frac{k}{2}

x = - 3; k \neq = - 2

Solution steps

x^{2} + x - 6 = (x + 3) (x + k)

Expand

(x + 3) (x + k) : x^{2} + k x + 3 x + 3 k

x^{2} + x - 6 = x^{2} + k x + 3 x + 3 k

Move

6

to the right side

x^{2} + x = x^{2} + k x + 3 x + 3 k + 6

Subtract

x^{2} + k x + 3 x

from both sides

x^{2} + x - (x^{2} + k x + 3 x) = x^{2} + k x + 3 x + 3 k + 6 - (x^{2} + k x + 3 x)

Simplify

- k x - 2 x = 3 k + 6

Factor

- k x - 2 x : - x (k + 2)

- x (k + 2) = 3 k + 6

Divide both sides by

- (k + 2); k \neq = - 2

x = - 3; k \neq = - 2

x, 6 y - 3 x = - 15

x, (x + y) - ((x + y) \frac{30}{100}) = 98

- \frac{1}{2} \cdot x + \frac{1}{4} = - \frac{21}{6} + 2 x

a, 3 b + 2 a = 6 (a + b)

3 x^{+} 14 x - 5 = 0

What is the answer to x^2+x-6=(x+3)(x+k), k/2 ?
The answer to x^2+x-6=(x+3)(x+k), k/2 is x=-3;\quad k\ne-2