What is the answer to (a^2-9)x=a^3+27 ?

The answer to (a^2-9)x=a^3+27 is x=(a^2-3a+9)/(a-3);\quad a\ne 3,a\ne-3

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(a^2-9)x=a^3+27

(a^{2} - 9) x = a^{3} + 27

x = \frac{a ^{2} - 3 a + 9}{a - 3}; a \neq = 3, a \neq = - 3

Solution steps

(a^{2} - 9) x = a^{3} + 27

Divide both sides by

a^{2} - 9; a \neq = 3, a \neq = - 3

x = \frac{a ^{2} - 3 a + 9}{a - 3}; a \neq = 3, a \neq = - 3

m, m + 5 n = 0

x = \frac{( - a )}{4} + \frac{2}{3} \cdot b

x, 7 x - 19 y + 1 = 0

d = 520 \cdot 45 \cdot 5

x, \frac{5}{2} \cdot x + 3 y = 1

What is the answer to (a^2-9)x=a^3+27 ?
The answer to (a^2-9)x=a^3+27 is x=(a^2-3a+9)/(a-3);\quad a\ne 3,a\ne-3