What are the solutions to the equation 5x^2-45x+100=0 ?

The solutions to the equation 5x^2-45x+100=0 are x=5,x=4

Find the zeros of 5x^2-45x+100=0

The zeros of 5x^2-45x+100=0 are x=5,x=4

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5 x^{2} - 45 x + 100 = 0

x = 5, x = 4

Solution steps

5 x^{2} - 45 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 45 ) \pm ( - 45 ) ^{2} - 4 \cdot 5 \cdot 100}{2 \cdot 5}

(- 45)^{2} - 4 \cdot 5 \cdot 100 = 5

x_{1, 2} = \frac{- ( - 45 ) \pm 5}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 45 ) + 5}{2 \cdot 5}, x_{2} = \frac{- ( - 45 ) - 5}{2 \cdot 5}

x = \frac{- ( - 45 ) + 5}{2 \cdot 5} : 5

x = \frac{- ( - 45 ) - 5}{2 \cdot 5} : 4

The solutions to the quadratic equation are:

x = 5, x = 4

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(64 x^{9} y^{- 18})^{\frac{1}{3}}

(x - 2) (x + 1) \leq 0

What are the solutions to the equation 5x^2-45x+100=0 ?
The solutions to the equation 5x^2-45x+100=0 are x=5,x=4
Find the zeros of 5x^2-45x+100=0
The zeros of 5x^2-45x+100=0 are x=5,x=4