What is the answer to r=sqrt(8^2+6^2+2(8)(1)) ?

The answer to r=sqrt(8^2+6^2+2(8)(1)) is r=2sqrt(29)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r=sqrt(8^2+6^2+2(8)(1))

r = 8^{2} + 6^{2} + 2 (8) (1)

r = 229

Decimal Notation

r = 10.77032 \dots

Solution steps

r = 8^{2} + 6^{2} + 2 (8) (1)

Simplify

8^{2} + 6^{2} + 2 (8) (1) : 229

r = 229

x, sin (y) = 1 - tan (x)

12 + x = 0

x, \frac{( x + 2 y )}{0.5} z = 128

2 \frac{x}{3} = - 10

\frac{3}{4} x - 20 = \frac{1}{4} x - 10

What is the answer to r=sqrt(8^2+6^2+2(8)(1)) ?
The answer to r=sqrt(8^2+6^2+2(8)(1)) is r=2sqrt(29)
Solve for r: r=sqrt(8^2+6^2+2(8)(1))
The solution is r=2sqrt(29)