What is the answer to f^1=25n,f^2=25nf^3=15nf^4=12 ?

The answer to f^1=25n,f^2=25nf^3=15nf^4=12 is n= f/(25)

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f^1=25n,f^2=25nf^3=15nf^4=12

f^{1} = 25 n, f^{2} = 25 n f^{3} = 15 n f^{4} = 12

n = \frac{f}{25}

Solution steps

f^{1} = 25 n

Switch sides

25 n = f^{1}

Apply rule

a^{1} = a

25 n = f

Divide both sides by

25

n = \frac{f}{25}

\frac{17}{3} = \frac{x}{1.5}

x - \frac{9}{10} x = \frac{- 131}{100}

x, 386.85 = 3.9 x^{102} g

x, p + \frac{2}{6} - 11 - \frac{p}{3} - \frac{1}{4} = 3 x - \frac{4}{12}

h = 0.033 (2.5 + 2 h) \cdot 25

What is the answer to f^1=25n,f^2=25nf^3=15nf^4=12 ?
The answer to f^1=25n,f^2=25nf^3=15nf^4=12 is n= f/(25)