What is the answer to solvefor a,3a+2b+c=6^{1/3} ?

The answer to solvefor a,3a+2b+c=6^{1/3} is a=(6^{1/3}-2b-c)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor a,3a+2b+c=6^{1/3}

solve for

a, 3 a + 2 b + c = 6^{\frac{1}{3}}

a = \frac{6 ^{\frac{1}{3}} - 2 b - c}{3}

Solution steps

3 a + 2 b + c = 6^{\frac{1}{3}}

Move

2 b

to the right side

3 a + c = 6^{\frac{1}{3}} - 2 b

Move

c

to the right side

3 a = 6^{\frac{1}{3}} - 2 b - c

Divide both sides by

3

a = \frac{6 ^{\frac{1}{3}} - 2 b - c}{3}

x, p^{2} x + q^{2} y = z

\frac{( 2 x - 5 )}{4} - \frac{( 8 x - 6 )}{5} = \frac{( 6 + 2 )}{7}

m = \frac{( 1 2 ^{7} \cdot 0.1 8 ^{3} \cdot 0.64 )}{( 2 4 ^{8} \cdot 0.81 )}

y, 2 y + 5 = x

- 55 c (c - 2.25) = - 11 c (5 c - 8.7) - 1.5

What is the answer to solvefor a,3a+2b+c=6^{1/3} ?
The answer to solvefor a,3a+2b+c=6^{1/3} is a=(6^{1/3}-2b-c)/3