What is the answer to z+3=(2(1-3z))/3 ?

The answer to z+3=(2(1-3z))/3 is z=-7/9

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z+3=(2(1-3z))/3

z + 3 = \frac{2 ( 1 - 3 z )}{3}

z = - \frac{7}{9}

Decimal

z = - 0.77777 \dots

Solution steps

z + 3 = \frac{2 ( 1 - 3 z )}{3}

Multiply both sides by

3

3 z + 9 = 2 (1 - 3 z)

Expand

2 (1 - 3 z) : 2 - 6 z

3 z + 9 = 2 - 6 z

Move

9

to the right side

3 z = - 6 z - 7

Move

6 z

to the left side

9 z = - 7

Divide both sides by

9

z = - \frac{7}{9}

e^{1} - 2 x = 17

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5 x + 3 x = 180

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