What is the answer to (x-2)^3-x^3+6x^2=7 ?

The answer to (x-2)^3-x^3+6x^2=7 is x= 5/4

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(x-2)^3-x^3+6x^2=7

(x - 2)^{3} - x^{3} + 6 x^{2} = 7

x = \frac{5}{4}

Decimal Notation

x = 1.25

Solution steps

(x - 2)^{3} - x^{3} + 6 x^{2} = 7

Expand

(x - 2)^{3} - x^{3} + 6 x^{2} : 12 x - 8

12 x - 8 = 7

Move

8

to the right side

12 x = 15

Divide both sides by

12

x = \frac{5}{4}

b, (b) 3^{5} \cdot 8^{5} = (d) 8^{8} \cdot 8^{- 3}

\frac{( 6 x )}{5} + \frac{7}{10} = 8

< a = (2 x + 5)

(4 x + 1) = 2

a = \frac{1}{2} \cdot 15 + 1.15 \cdot 3 + \frac{1}{3} \cdot 21 + \frac{6}{87} \cdot 90

What is the answer to (x-2)^3-x^3+6x^2=7 ?
The answer to (x-2)^3-x^3+6x^2=7 is x= 5/4
Solve for x: (x-2)^3-x^3+6x^2=7
The solution is x= 5/4