What is the answer to solvefor x,2x+2y+6z=2(x+y+3z) ?

The answer to solvefor x,2x+2y+6z=2(x+y+3z) is True for all x

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solvefor x,2x+2y+6z=2(x+y+3z)

solve for

x, 2 x + 2 y + 6 z = 2 (x + y + 3 z)

True for all x

Solution steps

2 x + 2 y + 6 z = 2 (x + y + 3 z)

Expand

2 (x + y + 3 z) : 2 x + 2 y + 6 z

2 x + 2 y + 6 z = 2 x + 2 y + 6 z

Move

2 y

to the right side

2 x + 6 z = 2 x + 6 z

Move

6 z

to the right side

2 x = 2 x

Move

2 x

to the left side

0 = 0

Both sides are equal

True for all x

0.5 x - 2 = 6 + 1 x

\frac{1}{4} y + \frac{1}{2} = 5

3 (4 x + 5) - 2 (x - 3) = 6 (2 x - 5) + 25, x = 13 x = 3

x, 5 x + 3 y = - 16.8

\frac{x}{1} + \frac{4}{2} = \frac{25}{10}

What is the answer to solvefor x,2x+2y+6z=2(x+y+3z) ?
The answer to solvefor x,2x+2y+6z=2(x+y+3z) is True for all x