What is the answer to solvefor x,2*4x(t-8)=6*12x(4-t) ?

The answer to solvefor x,2*4x(t-8)=6*12x(4-t) is x=0

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solvefor x,24x(t-8)=612x(4-t)

solve for

x, 2 \cdot 4 x (t - 8) = 6 \cdot 12 x (4 - t)

x = 0

Solution steps

2 \cdot 4 x (t - 8) = 6 \cdot 12 x (4 - t)

Expand

2 \cdot 4 x (t - 8) : 8 t x - 64 x

Expand

6 \cdot 12 x (4 - t) : 288 x - 72 t x

8 t x - 64 x = 288 x - 72 t x

Subtract

288 x - 72 t x

from both sides

8 t x - 64 x - (288 x - 72 t x) = 288 x - 72 t x - (288 x - 72 t x)

Simplify

80 t x - 352 x = 0

Factor

80 t x - 352 x : 16 x (5 t - 22)

16 x (5 t - 22) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0

m = 8 p (- 2.5)

(x^{2} - 4)^{3} = (x - 2)^{3} (x + 2)^{3}

x, x + y = 950

x, 3 y = 5 x + 16 t

w = \frac{( 2 f + 3 )}{( 8 - f )}

What is the answer to solvefor x,2*4x(t-8)=6*12x(4-t) ?
The answer to solvefor x,2*4x(t-8)=6*12x(4-t) is x=0