What is the answer to b=((3/20+1/2+1/15))/((31/3+2/9)) ?

The answer to b=((3/20+1/2+1/15))/((31/3+2/9)) is b= 129/1900

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b=((3/20+1/2+1/15))/((31/3+2/9))

b = \frac{( \frac{3}{20} + \frac{1}{2} + \frac{1}{15} )}{( \frac{31}{3} + \frac{2}{9} )}

b = \frac{129}{1900}

Decimal Notation

b = 0.06789 \dots

Solution steps

b = \frac{( \frac{3}{20} + \frac{1}{2} + \frac{1}{15} )}{( \frac{31}{3} + \frac{2}{9} )}

Simplify

\frac{\frac{3}{20} + \frac{1}{2} + \frac{1}{15}}{\frac{31}{3} + \frac{2}{9}} : \frac{129}{1900}

b = \frac{129}{1900}

x, 5 x + 6 y = 17.25

x - 496 = \frac{( 6.54 + 93.46 )}{100}

x, 17 x + 2 y = 36

\frac{5}{6} + x = \frac{3}{4} - (\frac{1}{3}) + \frac{4}{5}

3.8 x - (4.3 x + 3) = 5 - 2.2 x

What is the answer to b=((3/20+1/2+1/15))/((31/3+2/9)) ?
The answer to b=((3/20+1/2+1/15))/((31/3+2/9)) is b= 129/1900
Solve for b: b=((3/20+1/2+1/15))/((31/3+2/9))
The solution is b= 129/1900