What is the answer to m=(x+6)^2+(x-4)^2-2x^2 ?

The answer to m=(x+6)^2+(x-4)^2-2x^2 is x=(m-52)/4

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m=(x+6)^2+(x-4)^2-2x^2

m = (x + 6)^{2} + (x - 4)^{2} - 2 x^{2}

x = \frac{m - 52}{4}

Solution steps

m = (x + 6)^{2} + (x - 4)^{2} - 2 x^{2}

Switch sides

(x + 6)^{2} + (x - 4)^{2} - 2 x^{2} = m

Expand

(x + 6)^{2} + (x - 4)^{2} - 2 x^{2} : 4 x + 52

4 x + 52 = m

Move

52

to the right side

4 x = m - 52

Divide both sides by

4

x = \frac{m - 52}{4}

x, 7 x - (- 2 y) = 47

0.75 (8 b + 4) - 1 = 4 b + 140

x = 224 - 54

x, x + 14 = y - 17

\frac{3 \cdot ( x + 3 )}{2} = 3

What is the answer to m=(x+6)^2+(x-4)^2-2x^2 ?
The answer to m=(x+6)^2+(x-4)^2-2x^2 is x=(m-52)/4