What is the answer to x-2(1+3k)x+7(3+2k)=0 ?

The answer to x-2(1+3k)x+7(3+2k)=0 is x=-(-14k-21)/(1+6k);\quad k\ne-1/6

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x-2(1+3k)x+7(3+2k)=0

x - 2 (1 + 3 k) x + 7 (3 + 2 k) = 0

x = - \frac{- 14 k - 21}{1 + 6 k}; k \neq = - \frac{1}{6}

Solution steps

x - 2 (1 + 3 k) x + 7 (3 + 2 k) = 0

Move

7 (3 + 2 k)

to the right side

x - 2 (1 + 3 k) x = - 7 (2 k + 3)

Expand

x - 2 (1 + 3 k) x : - x - 6 k x

Expand

- 7 (2 k + 3) : - 14 k - 21

- x - 6 k x = - 14 k - 21

Factor

- x - 6 k x : - x (1 + 6 k)

- x (1 + 6 k) = - 14 k - 21

Divide both sides by

- (1 + 6 k); k \neq = - \frac{1}{6}

x = - \frac{- 14 k - 21}{1 + 6 k}; k \neq = - \frac{1}{6}

x, 6 x + 3 y = 17

p + \frac{142}{3} - \frac{51}{4} \cdot 3 \cdot \frac{1}{3} = 5

y, - 2 (- 3 y + 4 z + 25) + 5 y + 7 z = - 66

lo g_{10} (10) [3 + 2 lo g_{10} (10) (1 + x)] = 0

x, - 6 x + 4 y = 15

What is the answer to x-2(1+3k)x+7(3+2k)=0 ?
The answer to x-2(1+3k)x+7(3+2k)=0 is x=-(-14k-21)/(1+6k);\quad k\ne-1/6