What are the solutions to the equation x^2-8x-247=0 ?

The solutions to the equation x^2-8x-247=0 are x=4+sqrt(263),x=4-sqrt(263)

Find the zeros of x^2-8x-247=0

The zeros of x^2-8x-247=0 are x=4+sqrt(263),x=4-sqrt(263)

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x^{2} - 8 x - 247 = 0

x = 4 + 263, x = 4 - 263

Solution steps

x^{2} - 8 x - 247 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 247 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 247) = 2263

x_{1, 2} = \frac{- ( - 8 ) \pm 2 263}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 263}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 263}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 263}{2 \cdot 1} : 4 + 263

x = \frac{- ( - 8 ) - 2 263}{2 \cdot 1} : 4 - 263

The solutions to the quadratic equation are:

x = 4 + 263, x = 4 - 263

(\frac{a}{2})^{4}

4 x + 2 = 10

r^{2} - 2 r - 3 = 0

- \frac{2}{3} \cdot 1

9 x + 2 (x - 3) = 30

What are the solutions to the equation x^2-8x-247=0 ?
The solutions to the equation x^2-8x-247=0 are x=4+sqrt(263),x=4-sqrt(263)
Find the zeros of x^2-8x-247=0
The zeros of x^2-8x-247=0 are x=4+sqrt(263),x=4-sqrt(263)