What is the answer to solvefor y,a=t^4-5t^2+8t-5y ?

The answer to solvefor y,a=t^4-5t^2+8t-5y is y=-(a-t^4+5t^2-8t)/5

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solvefor y,a=t^4-5t^2+8t-5y

solve for

y, a = t^{4} - 5 t^{2} + 8 t - 5 y

y = - \frac{a - t ^{4} + 5 t ^{2} - 8 t}{5}

Solution steps

a = t^{4} - 5 t^{2} + 8 t - 5 y

Switch sides

t^{4} - 5 t^{2} + 8 t - 5 y = a

Move

t^{4}

to the right side

- 5 t^{2} + 8 t - 5 y = a - t^{4}

Move

5 t^{2}

to the right side

8 t - 5 y = a - t^{4} + 5 t^{2}

Move

8 t

to the right side

- 5 y = a - t^{4} + 5 t^{2} - 8 t

Divide both sides by

- 5

y = - \frac{a - t ^{4} + 5 t ^{2} - 8 t}{5}

x, f^{1} \cdot (x) = x - 1

x + 11 = 12

c = \frac{2}{( 2 5 )} - \frac{5}{( 2 + 5 )}

v, 7 E + 5 = v - \frac{( v \cdot 10 \cdot 45 )}{36000}

p = \frac{2}{1009 + 3}

What is the answer to solvefor y,a=t^4-5t^2+8t-5y ?
The answer to solvefor y,a=t^4-5t^2+8t-5y is y=-(a-t^4+5t^2-8t)/5