What is the answer to (3y-5)/3 =(2y+7)/9 ?

The answer to (3y-5)/3 =(2y+7)/9 is y= 22/7

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(3y-5)/3 =(2y+7)/9

\frac{3 y - 5}{3} = \frac{2 y + 7}{9}

y = \frac{22}{7}

Decimal

y = 3.14285 \dots

Solution steps

\frac{3 y - 5}{3} = \frac{2 y + 7}{9}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(3 y - 5) \cdot 9 = 3 (2 y + 7)

Expand

(3 y - 5) \cdot 9 : 27 y - 45

Expand

3 (2 y + 7) : 6 y + 21

27 y - 45 = 6 y + 21

Move

45

to the right side

27 y = 6 y + 66

Move

6 y

to the left side

21 y = 66

Divide both sides by

21

y = \frac{22}{7}

\frac{x}{36} - \frac{x}{40} = \frac{1}{6}

a, 5 a + 4 b = 57600

300 - 6 y + 2 y = 180

a, 5 a + 3 b = 21

f, f (2^{x} + 1) = 8^{x} + 3 \cdot 4^{x} + 2^{x} - 5

What is the answer to (3y-5)/3 =(2y+7)/9 ?
The answer to (3y-5)/3 =(2y+7)/9 is y= 22/7
Solve for y: (3y-5)/3 =(2y+7)/9
The solution is y= 22/7