What is the answer to solvefor x,p(xy)=2*2+y^2-xy-2xy ?

The answer to solvefor x,p(xy)=2*2+y^2-xy-2xy is x=(4+y^2)/(y(3+p));\quad p\ne-3

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solvefor x,p(xy)=2*2+y^2-xy-2xy

solve for

x, p (x y) = 2 \cdot 2 + y^{2} - x y - 2 x y

x = \frac{4 + y ^{2}}{y ( 3 + p )}; p \neq = - 3

Solution steps

p (x y) = 2 \cdot 2 + y^{2} - x y - 2 x y

Add similar elements:

- x y - 2 x y = - 3 x y

p x y = 2 \cdot 2 + y^{2} - 3 x y

Multiply the numbers:

2 \cdot 2 = 4

p x y = 4 + y^{2} - 3 x y

Expand

p (x y) : p x y

p x y = 4 + y^{2} - 3 x y

Move

3 x y

to the left side

p x y + 3 x y = 4 + y^{2}

Factor

p x y + 3 x y : x y (p + 3)

x y (p + 3) = 4 + y^{2}

Divide both sides by

y (p + 3); p \neq = - 3

x = \frac{4 + y ^{2}}{y ( 3 + p )}; p \neq = - 3

3 + a = 2 a

y, (x + 1) (y - 1) - 2 e^{- 2 x} + 1 = 0

\frac{13}{40} = 1 - (\frac{x}{7127})

x, - x + 2 y = - 5

x, 3 x - y = 90

What is the answer to solvefor x,p(xy)=2*2+y^2-xy-2xy ?
The answer to solvefor x,p(xy)=2*2+y^2-xy-2xy is x=(4+y^2)/(y(3+p));\quad p\ne-3