What is the answer to solvefor j,r(t)=2t^3i+t^2j ?

The answer to solvefor j,r(t)=2t^3i+t^2j is j= r/t-2it;\quad t\ne 0

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solvefor j,r(t)=2t^3i+t^2j

solve for

j, r (t) = 2 t^{3} i + t^{2} j

j = \frac{r}{t} - 2 i t; t \neq = 0

Solution steps

r (t) = 2 t^{3} i + t^{2} j

Switch sides

2 t^{3} i + t^{2} j = r t

2 t^{3} i + t^{2} j = r t

Move

2 t^{3} i

to the right side

t^{2} j = r t - 2 t^{3} i

Divide both sides by

t^{2}; t \neq = 0

j = \frac{r}{t} - 2 i t; t \neq = 0

2 - 6 y - 137 = 0

x, 3 y - 4 x + 2 = 0

\frac{333}{1000} = 1 - (\frac{x}{9395})

y, 2 x - y = x

x, \frac{1}{2} y = y - 23 x

What is the answer to solvefor j,r(t)=2t^3i+t^2j ?
The answer to solvefor j,r(t)=2t^3i+t^2j is j= r/t-2it;\quad t\ne 0