What is the answer to solvefor f,f0.9^{n+1}-9^n=72 ?

The answer to solvefor f,f0.9^{n+1}-9^n=72 is f=(72+9^n)/(0.9^{1+n)}

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solvefor f,f0.9^{n+1}-9^n=72

solve for

f, f 0. 9^{n + 1} - 9^{n} = 72

f = \frac{72 + 9 ^{n}}{0. 9 ^{1 + n}}

Solution steps

f \cdot 0. 9^{n + 1} - 9^{n} = 72

Move

9^{n}

to the right side

f \cdot 0. 9^{n + 1} = 72 + 9^{n}

Divide both sides by

0. 9^{n + 1}

f = \frac{72 + 9 ^{n}}{0. 9 ^{1 + n}}

m = c (1 + i t)

a - (a x \frac{1}{10}) = 3940000

x, 161 x + 295 y + 411 z = 3200

x, 2 x = 5 - y

x, a (x) = 2 \cdot 5 + 9 x - 6 + 10 \cdot 2 y

What is the answer to solvefor f,f0.9^{n+1}-9^n=72 ?
The answer to solvefor f,f0.9^{n+1}-9^n=72 is f=(72+9^n)/(0.9^{1+n)}