What is the answer to x=(13)/((3-2i)),x^4-4x^3-6x^2-4x+7^2 ?

The answer to x=(13)/((3-2i)),x^4-4x^3-6x^2-4x+7^2 is x=3+2i

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x=(13)/((3-2i)),x^4-4x^3-6x^2-4x+7^2

x = \frac{13}{( 3 - 2 i )}, x^{4} - 4 x^{3} - 6 x^{2} - 4 x + 7^{2}

x = 3 + 2 i

Solution steps

x = \frac{13}{( 3 - 2 i )}

Simplify

\frac{13}{3 - 2 i} : 3 + 2 i

x = 3 + 2 i

60 \cdot 0.18 + 0.82 x = 75

x, y + 3 x - 1 = 0

1.7 (2 x - 3) = 2.5 x - 2

a, p = 35 + 10 a + 5 b

x, x - \frac{6}{5} - 6 = y - \frac{( - 2 )}{- 6} - (- 2)

What is the answer to x=(13)/((3-2i)),x^4-4x^3-6x^2-4x+7^2 ?
The answer to x=(13)/((3-2i)),x^4-4x^3-6x^2-4x+7^2 is x=3+2i