What are the solutions to the equation 5x^2+11x+6=0 ?

The solutions to the equation 5x^2+11x+6=0 are x=-1,x=-6/5

Find the zeros of 5x^2+11x+6=0

The zeros of 5x^2+11x+6=0 are x=-1,x=-6/5

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5 x^{2} + 11 x + 6 = 0

x = - 1, x = - \frac{6}{5}

Decimal Notation

x = - 1, x = - 1.2

Solution steps

5 x^{2} + 11 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 5 \cdot 6}{2 \cdot 5}

1 1^{2} - 4 \cdot 5 \cdot 6 = 1

x_{1, 2} = \frac{- 11 \pm 1}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 11 + 1}{2 \cdot 5}, x_{2} = \frac{- 11 - 1}{2 \cdot 5}

x = \frac{- 11 + 1}{2 \cdot 5} : - 1

x = \frac{- 11 - 1}{2 \cdot 5} : - \frac{6}{5}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{6}{5}

x^{2} - c^{6}

\frac{x}{5} = - 8

y + 2 > 5

\frac{56 c - 14}{24 c - 6}

(\frac{4 x ^{8}}{2 x ^{6}})^{4}

What are the solutions to the equation 5x^2+11x+6=0 ?
The solutions to the equation 5x^2+11x+6=0 are x=-1,x=-6/5
Find the zeros of 5x^2+11x+6=0
The zeros of 5x^2+11x+6=0 are x=-1,x=-6/5