What is the answer to m*x-4x=3(8x-12)+15 ?

The answer to m*x-4x=3(8x-12)+15 is x=-(21)/(m-28);\quad m\ne 28

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m*x-4x=3(8x-12)+15

m \cdot x - 4 x = 3 (8 x - 12) + 15

x = - \frac{21}{m - 28}; m \neq = 28

Solution steps

m x - 4 x = 3 (8 x - 12) + 15

Expand

3 (8 x - 12) + 15 : 24 x - 21

m x - 4 x = 24 x - 21

Move

24 x

to the left side

m x - 28 x = - 21

Factor

m x - 28 x : x (m - 28)

x (m - 28) = - 21

Divide both sides by

m - 28; m \neq = 28

x = - \frac{21}{m - 28}; m \neq = 28

x = 15 - 2

5 (2 + x) - 9 = 200

\frac{1}{2} \cdot 1 - \frac{1}{4} = - 1, \frac{1}{x} \cdot \frac{1}{( 2 y )} = 8

x, - 8 y - 16 x + 40 = 0

n, c = 9 n + 15

What is the answer to m*x-4x=3(8x-12)+15 ?
The answer to m*x-4x=3(8x-12)+15 is x=-(21)/(m-28);\quad m\ne 28