What is the answer to solvefor x,p(x)=y^2+y^4-y^6 ?

The answer to solvefor x,p(x)=y^2+y^4-y^6 is x=(y^2+y^4-y^6)/p ;\quad p\ne 0

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solvefor x,p(x)=y^2+y^4-y^6

solve for

x, p (x) = y^{2} + y^{4} - y^{6}

x = \frac{y ^{2} + y ^{4} - y ^{6}}{p}; p \neq = 0

Solution steps

p (x) = y^{2} + y^{4} - y^{6}

Divide both sides by

p; p \neq = 0

x = \frac{y ^{2} + y ^{4} - y ^{6}}{p}; p \neq = 0

x, \frac{1}{z} \cdot x = 12

(7.2) y = - 2

x - 16 = 12

x, 2 (x + 2 y) = 2 x + 4 y

a, \frac{1}{( 1 - 7 )} = a + b \cdot 7

What is the answer to solvefor x,p(x)=y^2+y^4-y^6 ?
The answer to solvefor x,p(x)=y^2+y^4-y^6 is x=(y^2+y^4-y^6)/p ;\quad p\ne 0