What is the answer to solvefor x,(x-3)2+(y-2)2=25 ?

The answer to solvefor x,(x-3)2+(y-2)2=25 is x=(-2y+29)/2+3

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solvefor x,(x-3)2+(y-2)2=25

solve for

x, (x - 3) 2 + (y - 2) 2 = 25

x = \frac{- 2 y + 29}{2} + 3

Solution steps

(x - 3) \cdot 2 + (y - 2) \cdot 2 = 25

Move

(y - 2) 2

to the right side

(x - 3) \cdot 2 = - 2 y + 29

Divide both sides by

2

x - 3 = \frac{- 2 y + 29}{2}

Move

3

to the right side

x = \frac{- 2 y + 29}{2} + 3

x, 6 y + 2 x = - 3

x^{2} - 7 x + 10 = x^{2} + 5 x - 10

t (n) = \frac{n}{5 - 9}

2 x - {3 x - 4 [12 - 3 (x + 1)]} = 10

x, - 2 y - 20 = - 2 x - 6 x - 2

What is the answer to solvefor x,(x-3)2+(y-2)2=25 ?
The answer to solvefor x,(x-3)2+(y-2)2=25 is x=(-2y+29)/2+3