What is the answer to solvefor t,n=a^0(1+r)t ?

The answer to solvefor t,n=a^0(1+r)t is t= n/(1+r);\quad r\ne-1

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solvefor t,n=a^0(1+r)t

solve for

t, n = a^{0} (1 + r) t

t = \frac{n}{1 + r}; r \neq = - 1

Solution steps

n = a^{0} (1 + r) t

Switch sides

a^{0} (1 + r) t = n

Divide both sides by

1 + r; r \neq = - 1

t = \frac{n}{1 + r}; r \neq = - 1

x, 3 x + 2 y + 3 z = 38

f = 1 - 5

x, y - (- 4) = \frac{11}{2} \cdot (x - 0)

x, 4 x - 40 y = 8

x, x - y = 12 - x

What is the answer to solvefor t,n=a^0(1+r)t ?
The answer to solvefor t,n=a^0(1+r)t is t= n/(1+r);\quad r\ne-1