What is the answer to solvefor x,f^{-1}(x)=2 ?

The answer to solvefor x,f^{-1}(x)=2 is x=2f;\quad f\ne 0

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solvefor x,f^{-1}(x)=2

solve for

x, f^{- 1} (x) = 2

x = 2 f; f \neq = 0

Solution steps

f^{- 1} (x) = 2

Simplify

f^{- 1} : \frac{1}{f}

\frac{1}{f} x = 2

Multiply both sides by

f

x = 2 f; f \neq = 0

y, (2 x) = 14 x^{2} - 6 x y

x, - 8 x - (- 8 y) = - 36

x, 9 x - 11 y = 20

- 2 - 3 (5 v + 8) = 16 + 6 v

x, 5 x + 4 = 3 x - 2 y + 4

What is the answer to solvefor x,f^{-1}(x)=2 ?
The answer to solvefor x,f^{-1}(x)=2 is x=2f;\quad f\ne 0