What is the answer to solvefor t,deta=2^{n-1} ?

The answer to solvefor t,deta=2^{n-1} is t=(2^{n-1})/(dea);\quad d\ne 0

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solvefor t,deta=2^{n-1}

solve for

t, d e t a = 2^{n - 1}

t = \frac{2 ^{n - 1}}{d e a}; d \neq = 0

Solution steps

d e t a = 2^{n - 1}

Divide both sides by

d e a; d \neq = 0

t = \frac{2 ^{n - 1}}{d e a}; d \neq = 0

4 x + 9 = 10

5^{11} + x = 125

x, \frac{( 2 y + 5 x )}{y} = \frac{( 3 x )}{2}

x, x \cdot y = x + y + 1

x + (k - 1) \cdot k - 2 (k + 1) = 0

What is the answer to solvefor t,deta=2^{n-1} ?
The answer to solvefor t,deta=2^{n-1} is t=(2^{n-1})/(dea);\quad d\ne 0