What are the solutions to the equation (w^2)/8-w/2-4=0 ?

The solutions to the equation (w^2)/8-w/2-4=0 are w=8,w=-4

Find the zeros of (w^2)/8-w/2-4=0

The zeros of (w^2)/8-w/2-4=0 are w=8,w=-4

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\frac{w ^{2}}{8} - \frac{w}{2} - 4 = 0

w = 8, w = - 4

Solution steps

\frac{w ^{2}}{8} - \frac{w}{2} - 4 = 0

Find Least Common Multiplier of

8, 2 : 8

Multiply by LCM=

8

\frac{w ^{2}}{8} \cdot 8 - \frac{w}{2} \cdot 8 - 4 \cdot 8 = 0 \cdot 8

Simplify

w^{2} - 4 w - 32 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 32 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 32) = 12

w_{1, 2} = \frac{- ( - 4 ) \pm 12}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 4 ) + 12}{2 \cdot 1}, w_{2} = \frac{- ( - 4 ) - 12}{2 \cdot 1}

w = \frac{- ( - 4 ) + 12}{2 \cdot 1} : 8

w = \frac{- ( - 4 ) - 12}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

w = 8, w = - 4

196 - x^{2}

(2 x - 3)^{2} - (x + 5)^{2} = - 23

x + 1 = 1

∣ 12 - 4 x ∣ < - 13

22 \cdot 9

What are the solutions to the equation (w^2)/8-w/2-4=0 ?
The solutions to the equation (w^2)/8-w/2-4=0 are w=8,w=-4
Find the zeros of (w^2)/8-w/2-4=0
The zeros of (w^2)/8-w/2-4=0 are w=8,w=-4