What is the answer to (p-(3p-2))/3 =2+(p-4) ?

The answer to (p-(3p-2))/3 =2+(p-4) is p= 8/5

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(p-(3p-2))/3 =2+(p-4)

\frac{p - ( 3 p - 2 )}{3} = 2 + (p - 4)

p = \frac{8}{5}

Decimal Notation

p = 1.6

Solution steps

\frac{p - ( 3 p - 2 )}{3} = 2 + (p - 4)

Remove parentheses:

(a) = a

\frac{p - ( 3 p - 2 )}{3} = 2 + p - 4

Group like terms

\frac{p - ( 3 p - 2 )}{3} = p + 2 - 4

Add/Subtract the numbers:

2 - 4 = - 2

\frac{p - ( 3 p - 2 )}{3} = p - 2

Multiply both sides by

3

p - (3 p - 2) = 3 p - 6

Expand

p - (3 p - 2) : - 2 p + 2

- 2 p + 2 = 3 p - 6

Move

2

to the right side

- 2 p = 3 p - 8

Move

3 p

to the left side

- 5 p = - 8

Divide both sides by

- 5

p = \frac{8}{5}

3 x + \frac{1}{2} + \frac{a}{4} = 2 x

x, 10 x - 9 y = 11

x, (x - y) \cdot \frac{1}{2} = (x + y) \cdot \frac{3}{10}

2 x = \frac{102}{3}

7 (90 - x) = 3 (180 - x) - 10

What is the answer to (p-(3p-2))/3 =2+(p-4) ?
The answer to (p-(3p-2))/3 =2+(p-4) is p= 8/5
Solve for p: (p-(3p-2))/3 =2+(p-4)
The solution is p= 8/5