What is factor 81x^8-1 ?

The solution to factor 81x^8-1 is (9x^4+1)(3x^2+1)(3x^2-1)

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factor 81x^8-1

factor

81 x^{8} - 1

(9 x^{4} + 1) (3 x^{2} + 1) (3 x^{2} - 1)

Solution steps

81 x^{8} - 1

Apply exponent rules

= (9 x^{4})^{2} - 1^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(9 x^{4})^{2} - 1^{2} = (9 x^{4} + 1) (9 x^{4} - 1)

= (9 x^{4} + 1) (9 x^{4} - 1)

Factor

9 x^{4} - 1 : (3 x^{2} + 1) (3 x^{2} - 1)

= (9 x^{4} + 1) (3 x^{2} + 1) (3 x^{2} - 1)

\frac{4 2}{2}

(2 x - 1) - (2 x + 1) \leq 2

\frac{2.9}{2.9 - 3}

\frac{- 21}{- 5} = 4

15 - t + 8 t = - 13

What is factor 81x^8-1 ?
The solution to factor 81x^8-1 is (9x^4+1)(3x^2+1)(3x^2-1)