What is the answer to solvefor x,y=f(1+2x)+3 ?

The answer to solvefor x,y=f(1+2x)+3 is x=(y-3-f)/(2f);\quad f\ne 0

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solvefor x,y=f(1+2x)+3

solve for

x, y = f (1 + 2 x) + 3

x = \frac{y - 3 - f}{2 f}; f \neq = 0

Solution steps

y = f (1 + 2 x) + 3

Switch sides

f (1 + 2 x) + 3 = y

Move

3

to the right side

f (1 + 2 x) = y - 3

Divide both sides by

f; f \neq = 0

1 + 2 x = \frac{y - 3}{f}; f \neq = 0

Move

1

to the right side

2 x = \frac{y - 3}{f} - 1; f \neq = 0

Divide both sides by

2; f \neq = 0

x = \frac{y - 3 - f}{2 f}; f \neq = 0

\frac{( 3 a - 2 )}{3} + \frac{( 2 a + 3 )}{2} = a + \frac{7}{6}

x, 3 x_{2} y = 7

x, x + 7 y = c

\frac{3 ^{4} x}{3 ^{- 7}} = 3^{15}

x, (5 y - 21) + (6 x + 32) + 116 = 180

What is the answer to solvefor x,y=f(1+2x)+3 ?
The answer to solvefor x,y=f(1+2x)+3 is x=(y-3-f)/(2f);\quad f\ne 0