What is the general solution for solvefor t,cos(a)=mtan^3(a) ?

The general solution for solvefor t,cos(a)=mtan^3(a) is True for all t;\quad cos(a)=mtan^3(a)

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solvefor t,cos(a)=mtan^3(a)

solve for

t, cos (a) = m tan^{3} (a)

True for all t; cos (a) = m tan^{3} (a)

Solution steps

cos (a) = m tan^{3} (a)

Both sides are equal

True for all t; cos (a) = m tan^{3} (a)

x, 2 x - \frac{y}{2} = \frac{9}{2}

3 \frac{x}{4} - \frac{x}{12} = 6

g, x lo g_{10} (x) = lo g_{3} (+ lo g_{10} (x - 1))

x, \frac{1}{6} x - \frac{1}{2} y = 2

x, (x - y) \cdot 5 = 100

What is the general solution for solvefor t,cos(a)=mtan^3(a) ?
The general solution for solvefor t,cos(a)=mtan^3(a) is True for all t;\quad cos(a)=mtan^3(a)