What is the answer to solvefor x,f(2x-1)=4x+7 ?

The answer to solvefor x,f(2x-1)=4x+7 is x=(7+f)/(2(-2+f));\quad f\ne 2

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solvefor x,f(2x-1)=4x+7

solve for

x, f (2 x - 1) = 4 x + 7

x = \frac{7 + f}{2 ( - 2 + f )}; f \neq = 2

Solution steps

f (2 x - 1) = 4 x + 7

Expand

f (2 x - 1) : 2 x f - f

2 x f - f = 4 x + 7

Move

f

to the right side

2 x f = 4 x + 7 + f

Move

4 x

to the left side

2 x f - 4 x = 7 + f

Factor

2 x f - 4 x : 2 x (f - 2)

2 x (f - 2) = 7 + f

Divide both sides by

2 (f - 2); f \neq = 2

x = \frac{7 + f}{2 ( - 2 + f )}; f \neq = 2

(3 x + 1) = 4 mod 9

x, \frac{3}{5} x - \frac{5}{3} y = 1

x, - 2 x + 4 y = 68

x, f (x + 1) = f + 1

x, - x + 6 y = 9

What is the answer to solvefor x,f(2x-1)=4x+7 ?
The answer to solvefor x,f(2x-1)=4x+7 is x=(7+f)/(2(-2+f));\quad f\ne 2